Suggest a suitable physical situation for the following $a-t$ graph.
(N/A) The given $a-t$ graph shows that initially,the body is moving with a constant velocity (acceleration is zero).
Then,for a short interval of time,the acceleration increases to a maximum value and then decreases back to zero.
Finally,the body continues to move with a constant velocity again.
$A$ suitable physical situation for this graph is a hammer moving with a uniform velocity striking a nail. During the impact,the hammer experiences a brief period of high acceleration (deceleration) before continuing its motion or coming to rest.
Then,for a short interval of time,the acceleration increases to a maximum value and then decreases back to zero.
Finally,the body continues to move with a constant velocity again.
$A$ suitable physical situation for this graph is a hammer moving with a uniform velocity striking a nail. During the impact,the hammer experiences a brief period of high acceleration (deceleration) before continuing its motion or coming to rest.
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Similar Questions
$A$ particle has a velocity in the negative direction and a constant acceleration in the positive direction. Match the following columns:
Column $I$ Column $II$ $(A)$ Velocity-time graph $(p)$ Slope $\rightarrow$ negative $(B)$ Acceleration-time graph $(q)$ Slope $\rightarrow$ positive $(C)$ Displacement-time graph $(r)$ Slope $\rightarrow$ zero $(s)$ $|\text{Slope}| \rightarrow$ increasing $(t)$ $|\text{Slope}| \rightarrow$ decreasing $(u)$ $|\text{Slope}| \rightarrow$ constant
| Column $I$ | Column $II$ |
|---|---|
| $(A)$ Velocity-time graph | $(p)$ Slope $\rightarrow$ negative |
| $(B)$ Acceleration-time graph | $(q)$ Slope $\rightarrow$ positive |
| $(C)$ Displacement-time graph | $(r)$ Slope $\rightarrow$ zero |
| $(s)$ $|\text{Slope}| \rightarrow$ increasing | |
| $(t)$ $|\text{Slope}| \rightarrow$ decreasing | |
| $(u)$ $|\text{Slope}| \rightarrow$ constant |
Medium
View SolutionIn what different ways can velocity be changed?
Medium
View Solution$Assertion$ : Retardation is directly opposite to the velocity.
$Reason$ : Retardation is equal to the time rate of decrease of speed.
$Reason$ : Retardation is equal to the time rate of decrease of speed.
The relation between the displacement $x$ (in metre) and the time $t$ (in second) of a particle is $t = 2x^2 + 3x$. If the displacement of the particle is $25 \ cm$ from the origin $(x = 0)$, then the acceleration of the particle is:
If the displacement ($s$ in metre) of a moving particle in terms of time ($t$ in second) is $s = t^3 - 6t^2 + 18t + 9$,then the minimum velocity attained by the particle is (in $m \ s^{-1}$)
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